12(x^2)+51x+12=0

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Solution for 12(x^2)+51x+12=0 equation: 



12(x^2)+51x+12=0

a = 12; b = 51; c = +12;
Δ = b2-4ac
Δ = 512-4·12·12
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-45}{2*12}=\frac{-96}{24}
=-4
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+45}{2*12}=\frac{-6}{24}
=-1/4
$

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